Page 13: "In all cases , the power plant letter must be equal to or exceed either the maneuver drive letter or jump drive letter whichever is higher.'
Page 20 Patrol Cruiser 400 d-ton J-3, M-4, and the Power Plant must be equal to or exceed either the maneuver drive letter or jump drive letter whichever is higher which means that the Power Plant is 4.
Fuel Tankage = (0.1 x 400 x 3) + (10 x 4) = (40 x 3) + 40 = 120 + 40 = 160 d-tons.
120 d-tons of fuel does not support a J-3 or does not operate power plant at all.
Page 20, Patrol Cruiser (type T) (correction and omission): The fuel tankage should be 160 tons. Pulse lasers are installed. The correct cost is MCr 229.59 (after discount), and the ship takes 16 months to build.
From: "Jeff Zeitlin" <xxxxxx@freelancetraveller.com>
To: "TML" <xxxxxx@simplelists.com>
Sent: Sunday, July 2, 2017 6:12:58 PM
Subject: Re: [TML] SHIPBUILDING: Maneuver Drive/Power Plant fuel?
On Sun, 2 Jul 2017 17:48:36 -0700, you wrote to Freelance Traveller:
>On Sun, Jul 2, 2017 at 5:35 PM, Jeff Zeitlin <xxxxxx@freelancetraveller.com>
>wrote:
>
>> This question applies to Classic Traveller (Books 1-3) designs.
>>
>>
>>
>> I've been running the numbers for confirmation on some ship designs
>> that have been submitted, and I'm a bit confused all of a sudden. If I
>> look at the example ships from Book 2, the fuel tankage quoted seems
>> to be exactly what's needed for the specified Jump capability, but is
>> cited as "supports _n_ Jump _m_ and four weeks of operation". Is four
>> weeks of Power Plant/Maneuver fuel included in the allocation for the
>> Power Plant? If so, how do I determine how much fuel to add if I'm
>> designing the ship for extended-duration operations? If Power Plant
>> fuel is considered to be part of the cited fuel allocation, then how
>> can a 400td hull with J1 capability support 3xJ1 plus 4 weeks on 120td
>> of fuel?
>>
>
>Jeff, I just reread the 77', 81' and TTB descriptions, all of them have
>aprox. 220 tons of fuel. But all have around 120 tons of Cargo.
No, B2/1981 shows the 400td Patrol Cruiser shows 120 fuel:
>Patrol Cruiser (type T): Using a custom 400-ton hull, the patrol
>cruiser is a military vessel used for customs inspections, piracy
>suppression, and normal safety patrols. It has jump drive-F, maneuver
>drive-H, and power plant-H, giving the ship performance of jump3 and
>4-G acceleration. Fuel tankage of 120 tons supports the power plant
>and allows one jump-3. Adjacent to the bridge is a Model/3 computer.
>There are twelve staterooms and four low berths. There are four triple
>turrets installed, with fire control; two mount lasers and two mount
>missile racks. A GCarrier and a ship's boat are carried. There is a
>50-ton cargo bay, and the ship is streamlined.
>
>The patrol cruiser has a crew of 18: pilot, navigator, three
>engineers, medic, four gunners, and eight troops for boarding parties.
>Double occupancy for the gunners and troops is required. The ship
>costs MCr221.04 and takes 14 months to build.
Extracting the relevant line:
> Fuel tankage of 120 tons supports the power plant
>and allows one jump-3.
Recalling (and confirming from the book) that Jump Fuel is (disp * 0.1
* jump), the required jump fuel for the Type T is (400 * 0.1 * 3), or
120. Which is the cited fuel tankage. And yet it supports the Power
Plant as well. For zero fuel? Ummm... No. Not when there's a formula
that PP fuel is 10*Plant Rating. So for a power plant whose rating in
a given hull is '2', that means 20 tons. Note that I can't actually
find the cite for "four weeks", but that seems to be the Core
Assumption.
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